Pearson Edexcel 9PH0 · course-matched practice

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Actual marks20

Questions9

Topics represented9

Your paper aims for about 20 marks, so the final total may be slightly higher.

Question 1 · Electric circuits · 3 marks

Explain why the output across the fixed resistor rises with temperature.

Your answer

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Marking points

The thermistor's resistance falls as temperature rises.
In a potential divider, p.d. divides in proportion to resistance.
So a larger fraction of the supply p.d. is across the fixed resistor.

\(V_{\text{out}}\) = \(\dfrac{V_{\text{in}} \times R_{2}}{R_{1} + R_{2}}\).

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Question 2 · Materials · 3 marks

Explain how you would check that the ball has reached terminal velocity before timing.

Your answer

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Marking points

Place several markers at equal spacings below the surface.
Time the ball between successive markers.
Equal times show constant velocity.

Do not assume terminal velocity.

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Question 3 · Waves · 1 mark

What is the equation for double-slit fringe spacing?

Choose one answer A. w = \(\dfrac{\lambda s}{D}\) B. w = \(\dfrac{sD}{\lambda }\) C. w = \(\dfrac{\lambda D}{s}\) D. w = \(\dfrac{\lambda }{sD}\)

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Answer: C

Fringe spacing increases with λ and D and decreases with s.

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Question 4 · Astrophysics and cosmology · 2 marks

A star has peak wavelength 500 nm. Using Wien constant b = 2.90×10⁻³ m K, estimate its surface temperature.

Your answer

Use unit: K

Working

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Answer: 5800 K

T = \(\dfrac{b}{\lambda_{\text{max}}}\) = \(\dfrac{2.90\times 10^{-3}}{500\times 10^{-9}}\) = 5.8×10³ K.

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Question 5 · Capacitors · 3 marks

Explain why the charging current decreases with time.

Your answer

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Marking points

As the capacitor charges, its p.d. rises.
The p.d. across the resistor (V₀ − \(V_{C}\)) falls.
So the current I = \(\dfrac{V_{0} - V_{C}}{R}\) decreases.

The capacitor opposes further charge.

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Question 6 · Electric fields · 2 marks

A 2.0 nC positive charge experiences a force of 6.0 × 10⁻⁴ N. Calculate the electric field strength.

Your answer

Use unit: N/C

Working

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Answer: 3.0e5 N/C

E = \(\dfrac{F}{Q}\) = \(\dfrac{6.0\times 10^{-4}}{2.0\times 10^{-9}}\) = 3.0×10⁵ N/C.

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Question 7 · Gravitational fields · 2 marks

Calculate the gravitational field strength 7.0 × 10⁶ m from the centre of a planet of mass 6.0 × 10²⁴ kg. Use G = 6.67 × 10⁻¹¹ N m² kg⁻².

Your answer

Use unit: N/kg

Working

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Answer: 8.17 N/kg

g = \(\dfrac{GM}{r^{2}}\) = \(\dfrac{6.67\times 10^{-11} \times 6.0\times 10^{24}}{(7.0\times 10^{6})^{2}}\) ≈ 8.17 N/kg.

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Question 8 · Magnetic fields and induction · 2 marks

A 0.20 m wire carries 3.0 A perpendicular to a 0.50 T field. Calculate the magnetic force.

Your answer

Use unit: N

Working

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Answer: 0.3 N

F = BIL = 0.50 × 3.0 × 0.20 = 0.30 N.

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Question 9 · Measurements and uncertainties · 2 marks

A length is measured as 5.0 ± 0.1 cm. Calculate the percentage uncertainty.

Your answer

Use unit: %

Working

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Answer: 2 %

Percentage uncertainty = \(\dfrac{0.1}{5.0}\) × 100 = 2%.

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