A-Level Physics
Electric circuits
AQA 7408 — matched to your course.
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At a glance
Subtopics and learning goals
- Apply Kirchhoff's laws and circuit equations.
- Distinguish emf from terminal potential difference.
- Use resistivity and potential-divider relationships.
Revision notes
Current is rate of charge flow, I = \(\dfrac{\Delta Q}{\Delta t}\). Electromotive force (emf) is energy supplied per unit charge by a source; potential difference is energy transferred per unit charge between two points. A real source with internal resistance r and emf ε has terminal p.d. V = ε − Ir when delivering current.
Kirchhoff's first law expresses charge conservation at a junction; the sum of currents entering equals the sum leaving. The second law expresses energy conservation around a closed loop. For a uniform conductor R = \(\dfrac{\rho L}{A}\), where ρ is resistivity. Potential dividers use series components to obtain a fraction of a supply voltage, with the output depending on resistance ratios.
Current, charge and potential difference
Current is the rate of flow of charge, I = \(\dfrac{\Delta Q}{\Delta t}\). Potential difference is energy transferred per unit charge, V = \(\dfrac{W}{Q}\). Electromotive force describes energy supplied per unit charge by a source. These definitions are more useful than treating voltage as an unexplained 'push'.
Kirchhoff's first law follows from charge conservation: total current into a junction equals total current out. Kirchhoff's second law follows from energy conservation around a complete loop: the algebraic sum of emfs and potential differences is zero.
Resistance and resistivity
For an ohmic conductor at constant physical conditions, V = IR. Resistance depends on geometry and material. Resistivity is a material property related by R = \(\dfrac{\rho L}{A}\) for a uniform conductor. Increasing length increases resistance; increasing cross-sectional area decreases it.
Temperature can change resistivity. In metals, increased lattice vibration usually increases resistance. A filament lamp therefore has a curved I-V characteristic because its temperature rises as current increases.
Series, parallel and potential dividers
Series resistances add. Parallel combinations satisfy \(\dfrac{1}{R_{\text{total}}}\) = Σ(\(\dfrac{1}{R}\)). In parallel, branch potential differences are equal; currents divide according to branch resistance.
A potential divider produces an output voltage from a fraction of a supply. For two series resistors, \(\dfrac{V_{\text{out}}}{V_{\text{supply}}}\) depends on the resistance across which the output is taken. Sensors such as LDRs or thermistors can make the output depend on environmental conditions.
Internal resistance
A real source has internal resistance r. When current flows, some energy is transferred inside the source and terminal p.d. is lower than emf: V = ε - Ir. A graph of terminal p.d. against current has intercept ε and gradient -r.
Maximum power transfer and source efficiency can be reasoned from how current changes the internal voltage drop; always distinguish power delivered to the load from power dissipated internally.
Electrical power
P = IV. Combining with V = IR gives P = I²R and P = \(\dfrac{V^{2}}{R}\) where appropriate. These forms are not interchangeable without considering what quantity is held constant. Increasing R at fixed current increases power, but increasing R at fixed supply voltage decreases power.
Practical interpretation
When measuring an I-V characteristic, control temperature if the aim is to test ohmic behaviour. For resistivity, measure length and diameter carefully; because area depends on diameter squared, diameter uncertainty can dominate.
Exam technique
Use Kirchhoff's laws with a clear sign convention. Distinguish emf from terminal p.d., resistance from resistivity and current from charge. Before choosing a power equation, identify which circuit quantity is fixed by the situation.
Charge carriers and components
Current in a conductor is I = nAvq, where n is the number of charge carriers per unit volume and v is their drift velocity. Metals have very large n, so drift velocities are small (fractions of a millimetre per second).
An NTC thermistor's resistance falls as its temperature rises, and an LDR's resistance falls as light intensity increases. A semiconductor diode conducts in the forward direction above about 0.6 V and has a very high resistance in reverse.
A superconductor has zero resistivity below its critical temperature.
Potential dividers
For two resistors in series across \(V_{\text{in}}\), the output across R₂ is \(V_{\text{out}}\) = \(\dfrac{V_{\text{in}} \times R_{2}}{R_{1} + R_{2}}\). With a thermistor or LDR as one resistor, the output changes with temperature or light, making a sensor circuit.
Worked example
Worked example 1: A cell has emf 1.50 V, internal resistance 0.20 Ω and supplies 0.50 A. Lost volts Ir = 0.10 V, so terminal p.d. = 1.40 V.
Worked example 2: A cell has emf 1.50 V and internal resistance 0.20 Ω connected to a 2.80 Ω load. I = \(\dfrac{1.50}{2.80 + 0.20}\) = 0.50 A. Terminal p.d. = 1.50 - 0.50 × 0.20 = 1.40 V.
Misconception check
Emf is not a force. Its unit is the volt because it is energy supplied per unit charge, measured in joules per coulomb.
Assessment coverage
Practice this topic
2 questions available, worth 3 marks in total.
Retrieval cards
Define emf.
Energy supplied by a source per unit charge; ε = \(\dfrac{W}{Q}\).
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Course specification reference
This topic has been matched to the official course specification.
- AQA — A-level Physics (7408): 3.5 Electricity. Checked 6 September 2026. View official course specification