A-Level Physics
Electric fields
OCR H557 — matched to your course.
These revision notes are free. Premium unlocks the full question and retrieval-card bank for this topic.
Sign in to save this revision for later.
Matched to your course
This page is matched to OCR H557 so you can focus on the content for your course.
Revision hub
At a glance
Subtopics and learning goals
- Use Coulomb's law and definitions of electric field strength.
- Relate electric potential, potential difference and energy transfer.
- Analyse uniform and radial electric fields qualitatively and quantitatively.
- Define electric field strength as force per unit positive test charge.
- Use E = F/Q and E = V/d for appropriate fields.
- Apply the inverse-square character of the force between point charges qualitatively.
Revision notes
An electric field is a region in which a charge experiences an electric force. Electric field strength is force per unit positive test charge: E = \(\dfrac{F}{Q}\). For a point charge Q in vacuum, E = \(\dfrac{(\frac{1}{4\pi \varepsilon 0})Q}{r^{2}}\), directed away from positive charges and toward negative charges. Coulomb's law gives the magnitude of the force between point charges as F = \(\dfrac{1}{4\pi \varepsilon 0}\)|Qq|/r².
Electric potential V is potential energy per unit charge. A charge q moved through a potential difference ΔV has a change in electric potential energy ΔE = qΔV. Electric field strength is related to potential gradient; in a uniform field between parallel plates, E = \(\dfrac{V}{d}\) when edge effects are neglected. Equipotential surfaces are perpendicular to electric field lines, and no work is done moving a charge along a single equipotential.
A charged particle in an electric field experiences F = qE. Its acceleration follows from Newton's second law, with the force direction reversing for a negative charge.
Electric field strength
Electric field strength is force per unit positive test charge, E = \(\dfrac{F}{Q}\). Field direction is defined as the direction of force on a positive test charge. Around a positive point charge the field points outward; around a negative point charge it points inward.
For a uniform field between large parallel plates, E = \(\dfrac{V}{d}\) where edge effects are neglected. A charge q in an electric field experiences force F = qE, with direction depending on the sign of q.
Coulomb's law and inverse-square fields
The force between point charges has magnitude proportional to \(\dfrac{Qq}{r^{2}}\). The corresponding field of a point charge also follows an inverse-square dependence. Doubling distance reduces field strength and force to one quarter, provided the point-charge approximation remains valid.
Superposition applies: the resultant electric field is the vector sum of the fields produced by individual charges. Symmetry can simplify multi-charge problems.
Electric potential
Electric potential is potential energy per unit charge. Potential difference is work done per unit charge between two points. For a positive point charge, potential is positive and decreases towards zero with distance; for a negative charge it is negative.
Field strength is related to the gradient of potential. In one dimension, the field points in the direction of decreasing potential. Equipotential surfaces are everywhere perpendicular to electric field lines.
Energy changes
When a charge moves through a potential difference, electrical potential-energy change is ΔE = QΔV. Whether potential energy increases or decreases depends on charge sign and direction of motion.
Charged-particle motion
In a uniform electric field, a charged particle can undergo constant acceleration if relativistic effects and other forces are negligible. Motion can be analysed by combining F = qE with F = ma, often treating perpendicular directions separately.
Exam technique
Keep field strength and potential distinct: field is a vector, potential is a scalar. Use signs carefully for negative charges. In inverse-square questions, distinguish distance from the source from separation between two charges.
Radial potential and potential energy
Near a point charge Q, the electric potential is V = \(\dfrac{Q}{4\pi \varepsilon _{0}r}\), positive for a positive charge and zero at infinity. The electric potential energy of a charge q at distance r is E = \(\dfrac{Qq}{4\pi \varepsilon _{0}r}\). Here \(\dfrac{1}{4\pi \varepsilon _{0}}\) ≈ 8.99 × 10⁹ N m² C⁻², with ε₀ = 8.85 × 10⁻¹² F m⁻¹.
Charged particles between plates
A charged particle entering a uniform field at right angles to it has constant acceleration \(\dfrac{qE}{m}\) along the field and constant velocity across it, so it follows a parabolic path, just like a horizontal projectile.
Millikan's oil-drop experiment balanced the electric force \(\dfrac{qV}{d}\) against the weight of a charged drop and showed that charge is quantised in multiples of e.
Comparing gravitational and electric fields
Both point-source fields follow inverse-square laws for force and field strength, and both have potentials proportional to \(\dfrac{1}{r}\) with zero at infinity. Gravitational forces are always attractive, while electric forces can attract or repel.
Worked example
Worked example 1: A 2.0 nC positive charge experiences 6.0 × 10⁻⁴ N in a field. E = \(\dfrac{F}{Q}\) = \(\dfrac{6.0\times 10^{-4}}{2.0\times 10^{-9}}\) = 3.0×10⁵ N/C.
Worked example 2: Across parallel plates with 600 V separated by 0.025 m, E = \(\dfrac{V}{d}\) = \(\dfrac{600}{0.025}\) = 2.4 × 10⁴ V/m.
A 2.0 nC positive charge experiences 6.0 × 10⁻⁴ N. E = \(\dfrac{F}{Q}\) = 6.0×10⁻⁴ ÷ 2.0×10⁻⁹ = 3.0×10⁵ N/C.
Worked example 3: Between parallel plates at 480 V separated by 0.020 m, E = \(\dfrac{V}{d}\) = 2.4 × 10⁴ V/m.
Misconception check
Electric potential is a scalar, while electric field strength is a vector. A point can have zero potential without the electric field necessarily being zero.
Assessment coverage
Practice this topic
2 questions available, worth 3 marks in total.
Retrieval cards
Define electric field strength.
E = \(\dfrac{F}{Q}\): force per unit positive test charge.
This card is available with A-Level Physics premium access.
This card is available with A-Level Physics premium access.
This card is available with A-Level Physics premium access.
This card is available with A-Level Physics premium access.
This card is available with A-Level Physics premium access.
This card is available with A-Level Physics premium access.
This card is available with A-Level Physics premium access.
This card is available with A-Level Physics premium access.
This card is available with A-Level Physics premium access.
This card is available with A-Level Physics premium access.
Course specification reference
This topic has been matched to the official course specification.
- OCR — A Level Physics B (Advancing Physics) (H557): Electric fields — H557 specification.. Checked 17 September 2026. View official course specification