A-Level Physics
Oscillations
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At a glance
Subtopics and learning goals
- Recognise and use the defining relationships for simple harmonic motion.
- Describe energy transfers during an oscillation.
- Explain damping, forced oscillations and resonance.
- Recognise simple harmonic motion from acceleration proportional to and opposite displacement.
- Use T = 1/f and a = −ω²x.
- Describe energy transfers during an ideal simple harmonic oscillation.
Revision notes
Simple harmonic motion (SHM) occurs when acceleration is proportional to displacement from equilibrium and directed toward equilibrium: a = −ω²x. For ideal SHM, x can be written as A cos(ωt + φ), with period T = \(\dfrac{2\pi }{\omega }\) and frequency f = \(\dfrac{1}{T}\). Maximum speed is ωA.
In an ideal mass–spring oscillator, energy transfers continuously between kinetic energy and elastic potential energy while total mechanical energy remains constant. Speed is maximum at equilibrium and zero at the turning points. Real oscillators lose mechanical energy because of damping. Light damping gradually reduces amplitude; stronger damping can return a system to equilibrium more rapidly without sustained oscillation.
A periodic driving force produces forced oscillations. The response amplitude depends on driving frequency and damping. Near the natural frequency, energy transfer from the driver can be especially effective and the amplitude becomes large: this is resonance. Greater damping lowers and broadens the resonance peak.
Simple harmonic motion
Simple harmonic motion occurs when acceleration is proportional to displacement from equilibrium and directed towards equilibrium: a = -ω²x. The negative sign is essential because acceleration and displacement are opposite in direction.
Angular frequency is ω = 2πf and period T = \(\dfrac{1}{f}\). For ideal SHM, displacement can be represented sinusoidally. Velocity is maximum at equilibrium and zero at the turning points; acceleration is zero at equilibrium and maximum in magnitude at the turning points.
Energy in SHM
In an ideal oscillator, total mechanical energy is constant. For a mass-spring system, energy transfers between kinetic and elastic potential forms. At maximum displacement, kinetic energy is zero and potential energy is maximum. At equilibrium, potential energy relative to equilibrium is minimum and kinetic energy is maximum.
Energy relationships can be used to find speed at an intermediate displacement without explicitly using time.
Mass-spring and pendulum systems
For an ideal spring-mass oscillator, period depends on mass and spring constant. For a simple pendulum under the small-angle approximation, period depends on length and gravitational field strength but not on bob mass.
These formulae rely on model assumptions. Large pendulum amplitudes or non-linear spring behaviour invalidate the simplest SHM treatment.
Damping
Damping removes mechanical energy from an oscillator. Light damping causes amplitude to decrease gradually; heavy damping can suppress oscillation. The damping mechanism determines where the energy is transferred, for example to thermal energy in the surroundings.
Forced oscillations and resonance
A periodic driving force can produce forced oscillation. The response depends on driving frequency and damping. Near the system's natural frequency, amplitude can become large: resonance. Greater damping reduces the maximum resonant amplitude and broadens the response.
Resonance can be useful, as in tuning systems, or hazardous when structures are driven near a natural frequency.
Phase relationships
In SHM, acceleration is always in antiphase with displacement. Velocity is a quarter cycle out of phase with displacement in the ideal sinusoidal description. Phase diagrams or equations can help determine whether an oscillator is moving towards or away from equilibrium.
Exam technique
Use the defining equation a = -ω²x to identify SHM rather than simply saying motion repeats. At turning points, remember velocity is zero but acceleration is maximum. Check whether the question's model includes damping or forcing before assuming total mechanical energy is constant.
SHM equations
A mass–spring system has period T = 2π\(\sqrt{\dfrac{m}{k}}\).
A simple pendulum, for small angles, has period T = 2π\(\sqrt{\dfrac{l}{g}}\), independent of the mass and the amplitude.
The total energy of an oscillator is ½kA² (or ½mω²A²), shared between kinetic and potential energy.
Free oscillations and damping types
A free oscillation has no driving force and oscillates at its natural frequency. With light damping, the amplitude decays gradually over many cycles. Heavy damping returns it slowly without oscillating.
Worked example
Worked example 1: An oscillator has period 0.80 s. f = \(\dfrac{1}{T}\) = 1.25 Hz and ω = 2πf ≈ 7.85 rad/s.
Worked example 2: For a mass-spring system with m = 0.36 kg and k = 100 N/m, T = 2π\(\sqrt{\dfrac{m}{k}}\) = 2π√0.0036 = 0.377 s.
An oscillator has period 0.80 s. Its frequency is f = \(\dfrac{1}{T}\) = \(\dfrac{1}{0.80}\) = 1.25 Hz.
Worked example 3: For T = 0.80 s, angular frequency ω = \(\dfrac{2\pi }{T}\) = 7.85 rad/s.
Misconception check
At the equilibrium position in SHM the acceleration is zero, but the object is not necessarily at rest. Its speed is maximum there for an ideal oscillator.
Assessment coverage
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Retrieval cards
State the defining acceleration equation for SHM.
a = −ω²x.
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Course specification reference
This topic has been matched to the official course specification.
- Pearson Edexcel — Pearson Edexcel Level 3 Advanced GCE in Physics (9PH0): Oscillations — 9PH0 specification.. Checked 17 September 2026. View official course specification