Interactive practical

EMF and internal resistance

Vary the external load, measure terminal potential difference and current, then determine emf and internal resistance from a straight-line graph.

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A-Level Physics

EMF and internal resistance

Eduqas A420QS — matched to your course.

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At a glance

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Practical focuses1
Questions available2
Retrieval cards available1
Available question marks4

Practical focus

Practical method

Aim

Determine the emf and internal resistance of a cell from a graph of terminal p.d. against current.

Variables

Independent variable: load resistance (and so current)
Dependent variable: terminal p.d.
Control variables: the same cell; short readings to avoid the cell running down.

Apparatus

Method

  1. Connect the cell in series with the ammeter, variable resistor, protective resistor and switch; connect the voltmeter across the cell.
  2. Close the switch briefly and record V and I. Open it between readings.
  3. Repeat for at least six settings of the variable resistor.
  4. Plot V against I. From V = ε − Ir, the intercept is ε and the gradient is −r.

Sample results

Single cell.

I / AV / V
0.101.47
0.201.39
0.301.31
0.401.23
0.501.15

Analysis

V falls linearly with I. Intercept = 1.55 V = ε; gradient = −0.80 V A⁻¹, so r = 0.80 Ω.

Uncertainty

Voltmeter ±0.01 V and ammeter ±0.01 A give scatter of a few per cent. Using steepest and shallowest lines gives r = 0.80 ± 0.05 Ω.

Errors and improvements

ProblemEffectImprovement
Cell running downV driftsTake readings quickly; open the switch between them
Cell warmingr changesKeep currents modest
Voltmeter draws currentV slightly lowUse a high-resistance digital voltmeter

Risk assessment

HazardRiskControl measure
Short-circuiting the cellOverheatingInclude a protective resistor
Hot wiresBurnsAvoid large currents

Common mistakes

Worked analysis

From the graph: ε = 1.55 V. At I = 0.40 A, V = 1.23 V, so lost volts = 0.32 V and r = \(\dfrac{0.32}{0.40}\) = 0.80 Ω.

Common misconception

Emf is not a force; it is the energy supplied per coulomb, equal to the terminal p.d. only when no current flows.

Assessment coverage

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2 questions available, worth 4 marks in total.

Practical 2
Foundation 1Standard 1
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What is emf?

Energy supplied per unit charge by a source.

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