Interactive practical
Determining g by free fall
Measure drop heights and repeated electronic fall times, then use a height–time squared graph to determine gravitational acceleration.
Open interactive simulationA-Level Physics
Determining g by free fall
CCEA 1210 — matched to your course.
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At a glance
Practical focus
- Measure the motion of a freely falling object and determine gravitational acceleration from timed data.
Practical method
Aim
Determine the acceleration of free fall g by timing a falling object over several measured heights.
Variables
Independent variable: drop height h
Dependent variable: fall time t
Control variables: the same dense, small object; release from rest; the same timing method.
Apparatus
- Steel ball bearing
- Electromagnet release and trapdoor (or light gates)
- Electronic timer
- Metre rule and set square
- Clamp stand
Method
- Clamp the electromagnet so the ball hangs above a trapdoor; switching off the magnet starts the timer and the ball opening the trapdoor stops it.
- Measure the height h from the bottom of the ball to the trapdoor with a metre rule, using a set square to avoid parallax.
- Release the ball and record the time t. Repeat three times and take the mean.
- Repeat for at least five heights from 0.20 m to 1.00 m.
- Plot h against t². From s = ½gt², the gradient is \(\dfrac{g}{2}\).
Sample results
Steel ball released from rest; times are means of three repeats.
| h / m | mean t / s | t² / s² |
|---|---|---|
| 0.200 | 0.204 | 0.0416 |
| 0.400 | 0.288 | 0.0829 |
| 0.600 | 0.352 | 0.1239 |
| 0.800 | 0.405 | 0.1640 |
| 1.000 | 0.453 | 0.2052 |
Analysis
The graph of h against t² is a straight line. Gradient = \(\dfrac{1.000 - 0.200}{0.2052 - 0.0416}\) = 4.89 m s⁻², so g = 2 × 4.89 = 9.78 m s⁻². A small positive t-intercept shows a systematic delay in the magnet releasing the ball; using the gradient removes its effect.
Uncertainty
The repeat times at 0.200 m spread over about ±0.003 s, a percentage uncertainty of 1.5% in t and so 3% in t². Using the gradient of a best-fit line through all points, with steepest and shallowest lines, gives g = 9.8 ± 0.2 m s⁻².
Errors and improvements
| Problem | Effect | Improvement |
|---|---|---|
| Magnet releases the ball late | Every time too long (systematic) | Use the gradient, not a single \(\dfrac{h}{t^{2}}\) value; reduce the magnet current |
| Height measured to the wrong point | h too large or small | Measure from the bottom of the ball to the trapdoor |
| Air resistance | Times slightly long at large h | Use a small dense ball |
Risk assessment
| Hazard | Risk | Control measure |
|---|---|---|
| Falling ball | Bruising | Catch the ball in a sand tray |
| Stand toppling | Injury | Clamp the stand to the bench |
Common mistakes
- Plotting h against t instead of t² (a curve).
- Forgetting that the gradient is \(\dfrac{g}{2}\).
- Measuring h from the top of the ball.
Worked analysis
At h = 0.800 m, t = 0.405 s. g = \(\dfrac{2h}{t^{2}}\) = \(\dfrac{2 \times 0.800}{0.405^{2}}\) = 9.75 m s⁻². The graph value (9.78 m s⁻²) is more reliable because it uses every point.
Common misconception
A heavier ball does not fall faster in a vacuum; with negligible air resistance g is independent of mass.
Assessment coverage
Practice this practical
2 questions available, worth 4 marks in total.
Retrieval cards
What graph is used to find g by free fall?
h against t²; gradient = \(\dfrac{g}{2}\).
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How this practical fits your course
The label below uses the wording from your course specification.
- CCEA 1210 — Specification experiment: Appendix 4 experiment 4 – acceleration of free fall using light gates. Appendix 4 specifies determining free-fall acceleration using a falling object and light gates. Checked 18 September 2026. View official course source