Interactive practical

Resistance of a metal wire against temperature

Read a thermometer and ohmmeter during heating and cooling, subtract lead resistance and determine the temperature coefficient at 20 °C.

Open interactive simulation

A-Level Physics

Resistance of a metal wire against temperature

WJEC 1420QS — matched to your course.

These revision notes are free. Premium unlocks the full question and retrieval-card bank for this topic.

Sign in to save this revision for later.

Revision hub

At a glance

Start practice
Practical focuses1
Questions available2
Retrieval cards available1
Available question marks4

Practical focus

Practical method

Aim

Investigate how the resistance of a metal wire varies with temperature and find its temperature coefficient.

Variables

Independent variable: temperature
Dependent variable: resistance
Control variables: the same coil of wire; small measuring current.

Apparatus

Method

  1. Place the coil in a test tube of oil (or water if insulated) in a water bath with a thermometer.
  2. Measure the resistance at 0 °C using ice water.
  3. Heat the bath in steps of 20 °C, stirring and waiting for a steady resistance reading at each temperature.
  4. Plot R against temperature θ: R = R₀(1 + αθ), so the gradient is R₀α.

Sample results

Copper coil; small current from the ohmmeter.

θ / °CR / Ω
010.00
2010.78
4011.56
6012.34
8013.12

Analysis

R increases linearly with temperature, with gradient 0.039 Ω °C⁻¹ and R₀ = 10.00 Ω. α = \(\dfrac{0.039}{10.00}\) = 3.9 × 10⁻³ °C⁻¹, the accepted value for copper. Increased lattice vibrations scatter conduction electrons more often.

Uncertainty

Resistance is read to ±0.01 Ω (0.1%) and temperature to ±0.5 °C. The main uncertainty is the coil lagging the bath temperature.

Errors and improvements

ProblemEffectImprovement
Coil lags the bath temperatureR read at the wrong temperatureStir and wait for steady readings
Self-heating from the measuring currentR too highUse a small current
Resistance of leadsConstant offsetMeasure lead resistance and subtract

Risk assessment

HazardRiskControl measure
Hot waterScaldsHandle carefully
Electricity near waterShockLow voltage; keep connections dry

Common mistakes

Worked analysis

Gradient = \(\dfrac{13.12 - 10.00}{80}\) = 0.039 Ω °C⁻¹. α = \(\dfrac{\text{gradient}}{R_{0}}\) = \(\dfrac{0.039}{10.00}\) = 3.9 × 10⁻³ °C⁻¹.

Common misconception

Metals have higher resistance when hot because electrons collide more often with vibrating ions, not because there are fewer electrons.

Assessment coverage

Practice this practical

2 questions available, worth 4 marks in total.

Practical 2
Foundation 1Standard 1
Practise this practical

Retrieval cards

How does metal resistance vary with temperature?

Increases roughly linearly.

Premium retrieval card

This card is available with A-Level Physics premium access.

Premium retrieval card

This card is available with A-Level Physics premium access.

Premium retrieval card

This card is available with A-Level Physics premium access.

Premium retrieval card

This card is available with A-Level Physics premium access.

Premium retrieval card

This card is available with A-Level Physics premium access.

How this practical fits your course

The label below uses the wording from your course specification.

Further sources