Interactive practical

Speed of sound using a resonance tube

Hold tuning forks over a tube, raise and lower the water level to find the first two resonances, then determine the speed of sound and the end correction.

Open interactive simulation

A-Level Physics

Speed of sound using a resonance tube

CCEA 1210 — matched to your course.

These revision notes are free. Premium unlocks the full question and retrieval-card bank for this topic.

Sign in to save this revision for later.

Revision hub

At a glance

Start practice
Practical focuses1
Questions available2
Retrieval cards available1
Available question marks4

Practical focus

Practical method

Aim

Measure the speed of sound using resonance in a tube closed at one end, correcting for the end effect.

Variables

Independent variable: frequency of the tuning fork or speaker
Dependent variable: length of air column at first resonance
Control variables: air temperature; tube diameter.

Apparatus

Method

  1. Hold a sounding tuning fork over the open end and raise the tube until the sound is loudest: this is resonance with the first harmonic.
  2. Measure the air-column length L from the water surface to the top of the tube.
  3. Repeat for several frequencies, approaching resonance from above and below.
  4. The first resonance satisfies L + e = \(\dfrac{\lambda }{4}\), where e is the end correction.
  5. Plot L against \(\dfrac{1}{f}\): gradient = \(\dfrac{v}{4}\) and the intercept on the L axis is −e.

Sample results

Air at 20 °C; tube diameter 2.0 cm.

f / Hz1/f / 10⁻³ sL / m
2563.910.326
3203.130.260
3842.600.215
4802.080.171
5121.950.160

Analysis

L against \(\dfrac{1}{f}\) is a straight line with gradient 85 m s⁻¹, so v = 4 × 85 = 340 m s⁻¹. The line meets the L axis at −0.006 m, so the end correction e = 0.006 m (about 0.3 × diameter).

Uncertainty

Locating the loudest resonance is uncertain by about ±3 mm in L (about 1–2%). The graph method removes the need to know e and averages the random errors.

Errors and improvements

ProblemEffectImprovement
Judging maximum loudnessL uncertainApproach from both directions and average
Ignoring the end correctionv too lowUse the graph intercept
Fork not held centrallyWeak resonanceHold the fork just above the centre of the open end

Risk assessment

HazardRiskControl measure
Water spillsSlippery floorMop up spills
Glass cylinderBreakageSecure the cylinder

Common mistakes

Worked analysis

At 384 Hz, L = 0.215 m. With e = 0.006 m, \(\dfrac{\lambda }{4}\) = 0.221 m, so λ = 0.884 m and v = 384 × 0.884 = 339 m s⁻¹.

Common misconception

At first resonance a closed tube holds a quarter of a wavelength (node at the water, antinode just beyond the open end), not half.

Assessment coverage

Practice this practical

2 questions available, worth 4 marks in total.

Practical 2
Foundation 1Standard 1
Practise this practical

Retrieval cards

Resonance condition for a closed tube (first harmonic)?

L + e = \(\dfrac{\lambda }{4}\).

Premium retrieval card

This card is available with A-Level Physics premium access.

Premium retrieval card

This card is available with A-Level Physics premium access.

Premium retrieval card

This card is available with A-Level Physics premium access.

Premium retrieval card

This card is available with A-Level Physics premium access.

Premium retrieval card

This card is available with A-Level Physics premium access.

How this practical fits your course

The label below uses the wording from your course specification.

Further sources