Interactive practical
Output of a transformer
Wind different numbers of turns on the secondary of an iron-cored transformer, measure the output with an a.c. voltmeter, and compare the voltage ratio with the turns ratio.
Open interactive simulationGCSE Physics
Investigating transformer output
WJEC 3420QS — matched to your course.
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At a glance
Practical focus
- Investigate how the secondary output of an iron-cored transformer depends on the number of turns.
Practical method
Aim
Investigate how the number of turns on the secondary coil of a transformer affects the output potential difference.
Variables
Independent variable: number of turns on the secondary coil
Dependent variable: secondary (output) potential difference
Control variables: primary turns (100); primary ac potential difference (2.0 V); the same iron core.
Apparatus
- Laminated iron C-core
- Insulated wire for coils
- Low-voltage ac supply
- Two ac voltmeters
- Connecting leads
Method
- Wind 100 turns on one side of the iron core (primary) and connect it to a 2.0 V ac supply.
- Wind 50 turns on the other side (secondary) and connect an ac voltmeter across it.
- Switch on and record the primary and secondary potential differences.
- Repeat for 100, 150, 200 and 250 secondary turns.
- Compare \(\dfrac{Vs}{Vp}\) with \(\dfrac{Ns}{Np}\).
Sample results
Primary coil 100 turns at 2.0 V ac.
| Secondary turns | Secondary pd / V | Predicted pd (Vp × Ns/Np) / V |
|---|---|---|
| 50 | 0.95 | 1.0 |
| 100 | 1.9 | 2.0 |
| 150 | 2.8 | 3.0 |
| 200 | 3.7 | 4.0 |
| 250 | 4.6 | 5.0 |
Analysis
The output pd is directly proportional to the number of secondary turns: \(\dfrac{Vs}{Vp}\) ≈ \(\dfrac{Ns}{Np}\). Each measured value is slightly below the prediction because a real transformer is not 100% efficient: some energy is lost heating the coils and core, and not all the magnetic field links the two coils.
Errors and improvements
| Problem | Effect | Improvement |
|---|---|---|
| Energy losses | Vs below prediction | Use a laminated core and thicker wire; ensure the core is tightly closed |
| Turns miscounted | Wrong ratio | Count carefully and recount |
| DC supply used | No output | Use an ac supply |
Risk assessment
| Hazard | Risk | Control measure |
|---|---|---|
| Coils warm up | Burns | Switch off between readings |
| Higher output potential differences | Electric shock | Keep the supply pd low (2.0 V) and do not exceed about 12 V output |
Common mistakes
- Using a dc supply (a transformer needs a changing field).
- Inverting the turns ratio.
- Expecting the measured values to match the ideal prediction exactly.
Worked analysis
Np = 100, Vp = 2.0 V, Ns = 200. Ideal Vs = 2.0 × 200 ÷ 100 = 4.0 V. Measured 3.7 V. If the primary current is 0.50 A, ideal secondary current = VpIp ÷ Vs = (2.0 × 0.50) ÷ 4.0 = 0.25 A.
Common misconception
A transformer does not work with direct current; it needs an alternating current to produce a changing magnetic field.
Assessment coverage
Practice this practical
2 questions available, worth 4 marks in total.
Retrieval cards
What is the transformer equation?
\(\dfrac{Vp}{Vs}\) = \(\dfrac{Np}{Ns}\).
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This card is available with GCSE Physics premium access.
This card is available with GCSE Physics premium access.
This card is available with GCSE Physics premium access.
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How this practical fits your course
The label below uses the wording from your course specification.
- WJEC 3420QS — Specified practical work: Specified practical work – output of an iron-cored transformer. WJEC specifies investigation of the output of an iron-cored transformer; current WJEC teaching material varies secondary turns and measures secondary potential difference with low-voltage a.c. equipment. Checked 18 September 2026. View official course source